rebaridley rebaridley
  • 02-01-2021
  • Mathematics
contestada

Solve 15 ≥ -3x or 2/5x ≥ -2.

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Аноним Аноним
  • 02-01-2021

Answer:

[tex]15 \geqslant - 3x \\ \frac{15}{3} \geqslant - x \\ 5 \geqslant - x \\ - 5 \leqslant x[/tex]

[tex] \frac{2}{5}x \geqslant - 2 \\ x \geqslant - 2 \times \frac{5}{2} \\ x \geqslant - 5[/tex]

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chanelglez1 chanelglez1
  • 02-06-2022

Answer:

{x | x ≥ -5}

Step-by-step explanation:

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