Jtharris711 Jtharris711
  • 01-08-2018
  • Mathematics
contestada

The area of a square is 12 more than its perimeter. find the length of a side and its perimeter.

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sarajevo
sarajevo sarajevo
  • 01-08-2018

The area of a square is 12 more than its perimeter.

Let the side of the square be x.

Then area of the square =[tex] \\
\
x*x=x^2\\ [/tex]

and the perimeter=4x

As per the problem

Area-Perimeter=12

[tex] \\
\
x^2-4x=12\\
\\
\Rightarrow x^2-4x-12=0\\
\\
\Rightarrow x^2-6x+2x-12=0\\
\\
\Rightarrow x(x-6)+2(x-6)=0\\
\\
\Rightarrow (x-6)(x+2)=0\\
\\
\Rightarrow x=6,-2 [/tex]

x can not be negative. Hence x=6.

side length=x=6

Perimeter=4x=24

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