Answer:
[tex]x = \frac{15}{2}[/tex]
Step-by-step explanation:
We have that [tex]sin(\alpha) = \frac{side\ opositte}{hypotenuse}[/tex]
Then:
[tex]sin(30) = \frac{x}{15}\\\\sin(30) = \frac{1}{2}\\\\\frac{1}{2} = \frac{x}{15}\\\\15(\frac{1}{2}) = x\\\\x = \frac{15}{2}[/tex]
Finaly, the answer is [tex]\frac{15}{2}[/tex]
