Answer:
Sound intensity level of the sound = 140 dB
Explanation:
We have expression for sound intensity level
[tex]L=10log_{10}\left ( \frac{I}{I_0}\right )[/tex]
We have sound intensity, I = 100 W/m²
I₀ = 10⁻¹² W/m²
We need to find sound intensity level
Substituting
[tex]L=10log_{10}\left ( \frac{I}{I_0}\right )=10log_{10}\left ( \frac{100}{10^{-12}}\right )=10x14=140dB[/tex]
Sound intensity level of the sound = 140 dB
