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02-01-2020
Mathematics

contestada

In Exercise #13 above, how many different combinations would be possible if the three numbers do not have to be different (for example, 20-20-20 could be a combination)?

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tashana84nt tashana84nt

02-01-2020

Answer:

116 280

Step-by-step explanation:

number of combination = 20 x 19 x 18 x 17 = 116 280

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