starlitcas
starlitcas starlitcas
  • 04-03-2020
  • Mathematics
contestada

Why does (x-2)^2+9=0 have no real solutions?

Respuesta :

jimrgrant1 jimrgrant1
  • 04-03-2020

Answer:

see explanation

Step-by-step explanation:

Given

(x - 2)² + 9 = 0 ( subtract 9 from both sides )

(x - 2)² = - 9  ( take the square root of both sides )

x - 2 = ± [tex]\sqrt{-9}[/tex]

[tex]\sqrt{-9}[/tex] yields no real solutions

There is no real number when multiplied by itself gives - 9

In fact the solutions to [tex]\sqrt{-9}[/tex] are said to be imaginary, that is ± 3i

where i = [tex]\sqrt{-1}[/tex]

If interested investigate further.

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