Zorel01 Zorel01
  • 04-05-2020
  • Mathematics
contestada

Solve for x, or show there are no real solutions

(x-5)^2 =19

Respuesta :

mcarolynsilva
mcarolynsilva mcarolynsilva
  • 04-05-2020

Answer:

X= [tex]\sqrt{19}[/tex] +5

Step-by-step explanation:

First, in order to get rid of the "squared", take the square root of both sides of the equation.

[tex]\sqrt{(x+5)}[/tex] =[tex]\sqrt{19}[/tex]

This will turn into

x+5=[tex]\sqrt{19}[/tex]

Then we need to isolate the variable (x)

In order to do that, subtract 5 from both sides of the equation

x+5= [tex]\sqrt{19}[/tex]

  -5       -5

so we get

x=[tex]\sqrt{19}[/tex] +5

Answer Link
jpliff jpliff
  • 04-05-2020
5x^2=19
0.64
I believe this is correct I hope this helps
Answer Link

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