GillianLeziton
GillianLeziton GillianLeziton
  • 01-07-2020
  • Mathematics
contestada

[tex]\sqrt{-16} -\sqrt{-3} \sqrt{-3} -\sqrt{-4} \sqrt{-4} +3i-3i^{2} +3i^3[/tex]

Respuesta :

abidemiokin
abidemiokin abidemiokin
  • 08-07-2020

Answer:

4(i-1)

Step-by-step explanation:

Given the expression   [tex]\sqrt{-16} - \sqrt{-3} \sqrt{-3} -\sqrt{-4} \sqrt{-4}+3i-3i^{2} +3i^{3}[/tex]

On simplifying;

First we need to note that i² = -1 and √-1 = i

Substituting the values in the expression, it becomes;

= √16(√-1)-√(-3)(-3)-√(-4)(-4)+3i-3(-1)+3i(i²)

= 4i-√9-√16+3i+3-3i

= 4i-3-4+3

= 4i-4

= 4(i-1)

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