corbini7070 corbini7070
  • 01-12-2016
  • Mathematics
contestada

Given the function, f(x)=[square root] x+3-2 , calculate the average rate of change between x=6 and x=13.

Respuesta :

bhtaylor
bhtaylor bhtaylor
  • 01-12-2016
f(6) = 3-2 = 1
f(13) = 4-2 = 2
Rate of change:
(2-1)/(13-6) = 1/7
Answer Link
aramisdegaula1977
aramisdegaula1977 aramisdegaula1977
  • 06-09-2019

Answer:

Average rate for the given function is 1 / 7

Step-by-step explanation:

The average exchange rate corresponds to the ratio between the variation of the function and the variation of the variable. That is to say,

Average rate = [f (x2) - f (x1)] / (x2 -x1). Since x1 = 6 and x2 = 13, you have:

f (x1) = f (6) = sqrt (6 + 3) - 2 = 3 - 2 = 1

f (x2) = f (13) = sqrt (13 + 3) - 2 = 4 - 2 = 2

In this way,

Average rate = (2 -1) / (13 - 6) = 1/7

Answer Link

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