Respuesta :

Answer:

Option C, 15.14 units²

Step-by-step explanation:

area of the triangle,

6.82×5.04×sin(61.73)/2

= 15.1365001284..

= 15.14 units² (rounded to the nearest tenth)

The required area of the irregular triangle is 15.14 unit². Option C is correct.

Given that,
A figure of the triangle is shown,
Side AB = a =6.82
Side BC = b = 5.04
Angles, ∠A = 45.03°, ∠B = 61.73°.

What is the triangle?

The triangle is a geometric shape which includes 3 sides and the sum of the interior angle should not be greater than 180°.

What is altitude?

Altitude is perpendicular bisector to the side of the triangle from the opposite vertex of the triangle.

The area of the given triangle can be given as,
Area = 1/2 * a * b sinB
       =  1/2 * 6.82 * 5.04 * sin61.73°
       =  1/2 * 6.82 * 5.04 * 0.88
       =  15.14 unit²

Thus, the required area of the irregular triangle is 15.14 units². Option c is correct.


Learn more about triangles here:
https://brainly.com/question/2773823

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