how many real solution does the equation x^7+14x^5+16x^3+30x-560=0

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neharani neharani

03-01-2017
Mathematics

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how many real solution does the equation x^7+14x^5+16x^3+30x-560=0

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bhatiakartik10 bhatiakartik10 · Answer 1 · 2017-01-03T18:24:16+01:00

bhatiakartik10 bhatiakartik10

03-01-2017

Consider the given equation to be f(x) whose first derivative is positive for all real x. This implies f(x) is a strictly increasing function. Thus it has only 1 root.

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