yop1010 yop1010
  • 03-01-2017
  • Physics
contestada


How high has a 45 g golf ball been driven if it has a potential energy of 2.06 J?

Respuesta :

Аноним Аноним
  • 03-01-2017
Here, U = mgh

We have: m = 45 g = 0.045 Kg
U = 2.06 J, g = 9.8 m/s², h = ?

Substitute the values in the formula:
2.06 = 0.045 × 9.8 × h
2.06 = 0.441 × h
h = 2.06 / 0.441
h = 4.67 m

In short, your final answer would be 4.67 meters

Hope this helps!

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djsdoodle
djsdoodle djsdoodle
  • 03-01-2017
PE=mgh
2.06 J = 2.06 kg·m²/s² = (0.045 kg)·(9.8 m/s²)·h
where h is the height the ball has reached
Solve for h:
h = 2.06/(0.045·9.8) = 4.67 to the nearest hundredth
h = 4.67 m

Answer Link

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