AmmonE78780 AmmonE78780
  • 03-11-2022
  • Mathematics
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I am trying to make this statement true. 9/8 > x/2. How do I figure out what goes in x(numerator)?

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AdeoluwaX674806 AdeoluwaX674806
  • 03-11-2022
[tex]\frac{9}{8}>\frac{x}{2}[/tex]

we must solve x, so remove the 2 on the denominator multipliying on both sides by 2

[tex]\begin{gathered} \frac{9}{8}\times2>\frac{x}{2}\times2 \\ \\ \frac{18}{8}>x \\ \\ \frac{9}{4}>x \\ \\ x<\frac{9}{4} \end{gathered}[/tex]

x values ​​must be less than 9/4

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