DevanshS145496 DevanshS145496
  • 03-11-2022
  • Mathematics
contestada

what is the value of the expression when m=2 and n=-3. (4m^-3n^2)^2

Respuesta :

JaleighZ179727 JaleighZ179727
  • 03-11-2022

Giving the funtion

[tex](4m^{-3}n^2)^2[/tex]

m=2

n=-3

[tex](4(2)^{-3}(-3)^2)^2[/tex][tex](\frac{4}{2^3}(9))^2[/tex][tex](\frac{36}{2^3})^2[/tex][tex](\frac{36^2}{2^6})[/tex][tex](\frac{2^49^2}{2^2*2^4})=\frac{9^2}{2^2}[/tex][tex]\frac{81}{4}[/tex]

then the evaluated function in m=2 n=-3

has a value of 81/4

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