JohnaeT421715 JohnaeT421715
  • 03-11-2022
  • Mathematics
contestada

[tex]4a ^{2} - 12a - 16[/tex]I need help factoring

Respuesta :

RenleeE486058 RenleeE486058
  • 03-11-2022

4(a-4)(a+1)

1) Factorizing 4a²-12a -16

4a²-12a -16 Note that the GCD (4,12,16) is 4, Rewrite them

4a²- 4*3a - 4* 4

2) 4(a² -3a -4) Rewrite a² -3a -4 answering the question, What are the numbers whose sum is 3 and product is 4?

Answer:

1 -4 = -3

1 x -4 = -4

3) Hence, the answer is:

4a²-12a -16= 4(a-4)(a+1)

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