SaniahI633342 SaniahI633342
  • 03-11-2022
  • Mathematics
contestada

The one-to-one functions g and h are defined as follows.g(x) = 4x - 3h={(-6, 3), (-4, 7), (3, -8), (6, 4)Find the following

The onetoone functions g and h are defined as followsgx 4x 3h6 3 4 7 3 8 6 4Find the following class=

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EllistonR635756 EllistonR635756
  • 03-11-2022

It is given that

[tex]g(x)=4x-3[/tex]

Now to find the inverse of g

Let

[tex]\begin{gathered} y=4x-3 \\ 4x=y+3 \\ x=\frac{y+3}{4} \end{gathered}[/tex]

So

[tex]g^{-1}(x)=\frac{x+3}{4}[/tex]

Now we know that

[tex](g^{-1}.g)(x)=\text{ x}[/tex]

So

[tex](g^{-1}.g)(2)=2[/tex]

And since

[tex]h(-6)=3[/tex]

So

[tex]h^{-1}(3)=-6[/tex]

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