GalaG185179 GalaG185179
  • 03-11-2022
  • Mathematics
contestada

(4a²b) ?Simplify:(2a3b4)32a5710AB.4ab63с225510D4ab53

Respuesta :

NeyahZ468220 NeyahZ468220
  • 03-11-2022

We would apply the following laws of exponents

(x^y)^z = x^(yz)

a^c * a^d = a^(c + d)

a^c / a^d = a^(c - d)

The given expression is

(4a^2b)^2/(2a^3b^4)^3

By applying the first law above, it becomes

[4^2a^(2*2)b^2]/[2^3a^(3*3)b^(4*3)]

= [16a^4b^2]/[8a^9b^12]

by applying the second and third laws, we have

16/8 * a^(4 - 9) * b^(2 - 12)

= 2a^-5b^-10

Also, x^-1 = 1/x

Thus, the final expression would be

2/a^5b^10

Option C is correct

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