naymacruz naymacruz
  • 02-08-2017
  • Mathematics
contestada

Solve 5^x=81. 2
Round to the nearest ten-thousandth.

X≈????

Respuesta :

irspow
irspow irspow
  • 02-08-2017
Is that 5^x=81.2?

5^x=81.2  take the natural log of both sides

xln5=ln81.2  divide both sides by ln5

x=ln81.2/ln5

x≈2.7320  (to nearest ten-thousandth)

If you just meant 5^x=81, the process is the same

5^x=81  take the natural log of both sides

xln5=ln81  divide both sides by ln5

x=ln81/ln5

x≈2.7304  (to nearest ten-thousandth)


Answer Link

Otras preguntas

You are standing at the edge of a cliff which is 40 m tall. You throw an apple up with a speed of 15 m/s, and it accelerates downward at 9.81 m/s^2. How long do
spade realty sold lots for $23240 per hectare . what is total sales values if the lots in hectare were 2,3,4 ?
change -23/20 into a deciamal
Can someone help me? Im really bad at English ​
What’s the correct answer answer asap for brainlist
In this type of governance the power is in the hands of one person​
what do you do when you feel burned out? Any self care that you do try to create?​
yes haha yes what no oh yeah no nevermind wait yes
To apply for a job at the new store in the mole. is this a fragmentation sentence ​
What element is in period 4, group 12?