kaydeemyladyy
kaydeemyladyy kaydeemyladyy
  • 02-12-2017
  • Mathematics
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WojtekR
WojtekR WojtekR
  • 02-12-2017
[tex]a_1=11+(1-1)(4)=11+0=11\\\\a_2=11+(2-1)(4)=11+4=15[/tex]

so:

[tex]a_2=a_1+\,?\\\\15=11+\,?\\\\\boxed{?=4}[/tex]

Answer B.
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